If I understand this right it should be 15. 6! / (2! * (6-2)!) |

6C2 = 6! / (2!*(6-2)!) = 6*5/2 =3*5 =15 |

c1c2 c1c3 c1c4 c1c5 c1c6 c2c3 c2c4 c2c5 c2c6 c3c4 c3c5 c3c6 c4c5 c5c6
That's 14. Which one is missing? |

Paul: c4c6 is missing and Ricky is missing +1 at the end. |

15 videos
6*5/2=15
More general, it's n*(n-1)/2 – the number of ways that 2 objects can be chosen from among n objects, regardless of order. |

Actually, we shot 15 videos. I think that adds up, doesn't it? Thanks for playing!
-Amanda from Extensis |