If I understand this right it should be 15.
6! / (2! * (6-2)!) |
6C2
= 6! / (2!*(6-2)!)
= 6*5/2
=3*5
=15 |
c1c2 c1c3 c1c4 c1c5 c1c6
c2c3 c2c4 c2c5 c2c6
c3c4 c3c5 c3c6
c4c5 c5c6
That's 14. Which one is missing? |
Paul: c4c6 is missing and Ricky is missing +1 at the end. |
15 videos
6*5/2=15
More general, it's n*(n-1)/2 – the number of ways that 2 objects can be chosen from among n objects, regardless of order. |
Actually, we shot 15 videos.
I think that adds up, doesn't it?
Thanks for playing!
-Amanda from Extensis |
